Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor. $\newline$ $g^2 - 2g - 3$

View step-by-step help

View step-by-step help

Factor quadratics

Full solution

Q. Factor.

\newline

g^2 - 2g - 3

Identify Form of Quadratic Trinomial: Identify the form of the quadratic trinomial, which is $g^2 - 2g - 3$ .
Find Multiplying and Adding Numbers: Look for two numbers that multiply to $-3$ (the constant term) and add up to $-2$ (the coefficient of the linear term).
Use Numbers for Factored Form: The numbers $-3$ and $1$ work because $-3 \times 1 = -3$ and $-3 + 1 = -2$ .
Check Factoring by Expanding: Write the factored form using these two numbers: $(g - 3)(g + 1)$ .
Simplify Expanded Form: Check the factoring by expanding $(g - 3)(g + 1)$ to see if it gives the original expression.
Simplify Expanded Form: Check the factoring by expanding $(g - 3)(g + 1)$ to see if it gives the original expression.Expanding gives: $g^2 + g - 3g - 3$ , which simplifies to $g^2 - 2g - 3$ .

More problems from Factor quadratics

Question

Factor out the greatest common factor. If the greatest common factor is

1

, just retype the polynomial.

\newline

4x^3 - 6x^2

\newline

Posted 2 months ago

Question

x^4 + 8x^2 + 16

\newline

All factors in your answer should have integer coefficients.

\newline

Posted 2 months ago

Question

Find the binomial that completes the factorization.

\newline

t^3 + u^3 = (\underline{\hspace{1cm}}) (t^2 - tu + u^2)

Posted 2 months ago

Question

\newline

g^2 - 11g + 18

Posted 2 months ago

Question

\newline

2y^3 - y^2 + 16y - 8

\newline

\newline

Posted 2 months ago

Question

\newline

2x^8 + 7x^2

\newline

Posted 3 months ago

Question

\newline

9y^{12} + 4y^5 - y^2

\newline

Posted 3 months ago

Question

\newline

6a^4 + 3a^3 - a + 2

\newline

Posted 3 months ago

Question

\newline

4c^7 - 2c^5 + c^2 - 5

\newline

Posted 3 months ago

Question

\newline

7m^9 + 2m^6 - m^3 + 4m - 10

\newline

Posted 3 months ago