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Factor completely.

2x^(2)+5x+3
Answer:

Factor completely.\newline2x2+5x+3 2 x^{2}+5 x+3 \newlineAnswer:

Full solution

Q. Factor completely.\newline2x2+5x+3 2 x^{2}+5 x+3 \newlineAnswer:
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2x2+5x+32x^2 + 5x + 3. By comparing 2x2+5x+32x^2 + 5x + 3 with the standard form ax2+bx+cax^2 + bx + c, we find that a=2a = 2, b=5b = 5, and c=3c = 3.
  2. Find two numbers: Find two numbers that multiply to aca*c (23=62*3 = 6) and add up to bb (55).\newlineWe need to find two numbers that multiply to 66 and add up to 55. The numbers 22 and 33 fit this requirement because 23=62*3 = 6 and 2+3=52+3 = 5.
  3. Rewrite middle term: Rewrite the middle term 5x5x using the two numbers found in Step 22.\newlineWe can express 5x5x as the sum of 2x2x and 3x3x. Therefore, we rewrite the expression as 2x2+2x+3x+32x^2 + 2x + 3x + 3.
  4. Factor by grouping: Factor by grouping.\newlineWe group the terms as follows: 2x2+2x2x^2 + 2x + 3x+33x + 3.\newlineNow we factor out the common factors from each group.\newlineFrom the first group, we can factor out 2x2x, giving us 2x(x+1)2x(x + 1).\newlineFrom the second group, we can factor out 33, giving us 3(x+1)3(x + 1).
  5. Write factored form: Write the factored form of the expression.\newlineSince both groups contain the factor (x+1)(x + 1), we can factor this out to get the final factored form of the expression: (2x+3)(x+1)(2x + 3)(x + 1).