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Factor completely: 2(4x-3)^(4)+(4x-3)^(5) Answer:

Factor completely:\newline2(4x−3)4+(4x−3)5 2(4 x-3)^{4}+(4 x-3)^{5} \newlineAnswer:

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Full solution

Q. Factor completely:\newline2(4x−3)4+(4x−3)5 2(4 x-3)^{4}+(4 x-3)^{5} \newlineAnswer:
  1. Identify common factor: Identify the common factor in both terms.\newlineThe common factor in both terms is (4x−3)4(4x-3)^{4} since it is present in both terms of the expression.
  2. Factor out: Factor out the common factor from the expression.\newlineWe can factor (4x−3)4(4x-3)^{4} out of both terms to get (4x−3)4(2+(4x−3))(4x-3)^{4}(2 + (4x-3)).
  3. Simplify expression: Simplify the expression inside the parentheses.\newlineSimplifying the expression inside the parentheses gives us (4x−3)4(2+4x−3)(4x-3)^{4}(2 + 4x - 3).
  4. Combine like terms: Combine like terms inside the parentheses.\newlineCombining like terms 22 and −3-3 gives us (4x−3)4(4x−1)(4x-3)^{4}(4x - 1).
  5. Write final form: Write down the final factored form.\newlineThe completely factored form of the expression is (4x−3)4(4x−1)(4x-3)^{4}(4x - 1).

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