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factor as the product of two binomials. x23x10x^2-3x-10

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Q. factor as the product of two binomials. x23x10x^2-3x-10
  1. Identify Coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is x23x10x^2 - 3x - 10. Here, the coefficient of x2x^2 (a)(a) is 11, the coefficient of xx (b)(b) is 3-3, and the constant term (c)(c) is 10-10.
  2. Find Multiplying Numbers: Determine two numbers that multiply to give the product of aca\cdot c (which is 10-10) and add up to bb (which is 3-3).\newlineWe need to find two numbers that multiply to 10-10 and add up to 3-3. The numbers 5-5 and 22 satisfy these conditions because (5)2=10(-5) \cdot 2 = -10 and (5)+2=3(-5) + 2 = -3.
  3. Write Split Expression: Write the quadratic expression using the two numbers found in the previous step to split the middle term.\newlineThe expression becomes x25x+2x10x^2 - 5x + 2x - 10. We have split the middle term 3x-3x into 5x-5x and 2x2x.
  4. Factor by Grouping: Factor by grouping.\newlineGroup the terms to factor by grouping: (x25x)+(2x10)(x^2 - 5x) + (2x - 10).
  5. Factor Common Factors: Factor out the greatest common factor from each group.\newlineFrom the first group x25xx^2 - 5x, we can factor out an xx to get x(x5)x(x - 5). From the second group 2x102x - 10, we can factor out a 22 to get 2(x5)2(x - 5).
  6. Write Factored Form: Write the factored form by combining the common factors.\newlineSince both groups contain the factor (x5)(x - 5), the factored form is (x5)(x+2)(x - 5)(x + 2).