Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor. $\newline$ $6j^2 + 24j + 18$

View step-by-step help

View step-by-step help

Factor quadratics

Full solution

Q. Factor.

\newline

6j^2 + 24j + 18

Identify Common Factor: First, look for a common factor in all terms. $6j^2 + 24j + 18$ can be divided by $6$ .
Divide by Common Factor: Divide each term by $6$ . $\newline$ $6j^2 \div 6 = j^2$ , $24j \div 6 = 4j$ , $18 \div 6 = 3$ . $\newline$ So, $6j^2 + 24j + 18 = 6(j^2 + 4j + 3)$ .
Factor Quadratic Inside: Now, factor the quadratic inside the parentheses. $\newline$ We need two numbers that multiply to $3$ and add to $4$ .
Find Correct Numbers: The numbers are $3$ and $1$ because $3 \times 1 = 3$ and $3 + 1 = 4$ . So, $j^2 + 4j + 3$ can be factored as $(j + 3)(j + 1)$ .
Write Final Factored Form: Write the final factored form including the $6$ we factored out earlier. $\newline$ $6(j^2 + 4j + 3) = 6(j + 3)(j + 1)$ .

More problems from Factor quadratics

Question

Factor out the greatest common factor. If the greatest common factor is

1

, just retype the polynomial.

\newline

4x^3 - 6x^2

\newline

Posted 2 months ago

Question

x^4 + 8x^2 + 16

\newline

All factors in your answer should have integer coefficients.

\newline

Posted 2 months ago

Question

Find the binomial that completes the factorization.

\newline

t^3 + u^3 = (\underline{\hspace{1cm}}) (t^2 - tu + u^2)

Posted 2 months ago

Question

\newline

g^2 - 11g + 18

Posted 2 months ago

Question

\newline

2y^3 - y^2 + 16y - 8

\newline

\newline

Posted 2 months ago

Question

\newline

2x^8 + 7x^2

\newline

Posted 3 months ago

Question

\newline

9y^{12} + 4y^5 - y^2

\newline

Posted 3 months ago

Question

\newline

6a^4 + 3a^3 - a + 2

\newline

Posted 3 months ago

Question

\newline

4c^7 - 2c^5 + c^2 - 5

\newline

Posted 3 months ago

Question

\newline

7m^9 + 2m^6 - m^3 + 4m - 10

\newline

Posted 3 months ago