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Factor. $\newline$ $4h^2 - 25$

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Factor quadratics: special cases

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Q. Factor.

\newline

4h^2 - 25

Determine method: Determine the appropriate method to factor $4h^2 - 25$ . The expression is a difference of squares because it can be written as $a^2 - b^2$ , where both terms are perfect squares.
Identify terms: Identify the terms in the form of $a^2 - b^2$ . $4h^2$ can be written as $(2h)^2$ because $2h \times 2h = 4h^2$ . $25$ can be written as $5^2$ because $5 \times 5 = 25$ . So, $4h^2 - 25$ can be rewritten as $(2h)^2 - 5^2$ .
Apply formula: Apply the difference of squares formula to factor the expression. $\newline$ The difference of squares formula is $a^2 - b^2 = (a - b)(a + b)$ . $\newline$ Using this formula, we get $(2h)^2 - 5^2 = (2h - 5)(2h + 5)$ .

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