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Factor.\newline4d2+12d+54d^2 + 12d + 5

Full solution

Q. Factor.\newline4d2+12d+54d^2 + 12d + 5
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 4d2+12d+54d^2 + 12d + 5 by comparing it with the standard form ax2+bx+cax^2 + bx + c.
    a=4a = 4
    b=12b = 12
    bb00
  2. Find Multiplying Numbers: Find two numbers that multiply to aca*c (which is 45=204*5=20) and add up to bb (which is 1212).\newlineWe need to find two numbers that satisfy these conditions.
  3. Check Factors: After checking possible pairs of factors of 2020, we find that 22 and 1010 multiply to 2020 and add up to 1212.\newlineSo the two numbers we are looking for are 22 and 1010.\newline2×10=202 \times 10 = 20\newline2+10=122 + 10 = 12
  4. Rewrite Middle Term: Rewrite the middle term (12d12d) using the two numbers we found (22 and 1010) to split it into two terms.\newline4d2+12d+54d^2 + 12d + 5 becomes 4d2+2d+10d+54d^2 + 2d + 10d + 5.
  5. Factor by Grouping: Factor by grouping. Group the first two terms and the last two terms.\newline(4d2+2d)+(10d+5)(4d^2 + 2d) + (10d + 5)
  6. Factor out Common Factor: Factor out the greatest common factor from each group. 2d(2d+1)+5(2d+1)2d(2d + 1) + 5(2d + 1)
  7. Factor out Common Factor: Factor out the greatest common factor from each group.\newline2d(2d+1)+5(2d+1)2d(2d + 1) + 5(2d + 1)Since both groups contain the common factor (2d+1)(2d + 1), factor this out.\newlineThe factored form of the expression is (2d+1)(2d+5)(2d + 1)(2d + 5).