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Factor.\newline3n2+10n+33n^2 + 10n + 3

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Q. Factor.\newline3n2+10n+33n^2 + 10n + 3
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3n2+10n+33n^2 + 10n + 3. Compare 3n2+10n+33n^2 + 10n + 3 with the standard form ax2+bx+cax^2 + bx + c. a=3a = 3 bb00 bb11
  2. Find numbers for aca*c: Find two numbers that multiply to aca*c (which is 33=93*3=9) and add up to bb (which is 1010).\newlineWe need to find two numbers that satisfy these conditions.\newlineAfter checking possible factors of 99, we find that 11 and 99 are the numbers we are looking for because 19=91*9 = 9 and 1+9=101+9 = 10.
  3. Rewrite middle term: Rewrite the middle term 10n10n using the two numbers 11 and 99 found in Step 22.\newline3n2+10n+33n^2 + 10n + 3 can be rewritten as 3n2+n+9n+33n^2 + n + 9n + 3.
  4. Factor by grouping: Factor by grouping.\newlineGroup the terms to factor out common factors:\newlineGroup 3n2+n3n^2 + n and 9n+39n + 3.\newline3n2+n3n^2 + n can be factored as n(3n+1)n(3n + 1).\newline9n+39n + 3 can be factored as 3(3n+1)3(3n + 1).
  5. Factor out common factor: Factor out the common binomial factor (3n+1)(3n + 1).\newlineWe now have n(3n+1)+3(3n+1)n(3n + 1) + 3(3n + 1).\newlineFactor out (3n+1)(3n + 1) to get (3n+1)(n+3)(3n + 1)(n + 3).