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Factor.\newline3d2+5d+23d^2 + 5d + 2

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Q. Factor.\newline3d2+5d+23d^2 + 5d + 2
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3d2+5d+23d^2 + 5d + 2 by comparing it with the standard form ax2+bx+cax^2 + bx + c.
    a=3a = 3
    b=5b = 5
    bb00
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 32=63*2=6) and add up to bb (which is 55).\newlineThe two numbers that satisfy these conditions are 22 and 33 because:\newline23=62 * 3 = 6\newline2+3=52 + 3 = 5
  3. Rewrite middle term: Rewrite the middle term 5d5d using the two numbers found in the previous step 22 and 33 to split it into two terms.\newline3d2+5d+23d^2 + 5d + 2 can be rewritten as:\newline3d2+2d+3d+23d^2 + 2d + 3d + 2
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together, then factor out the common factors from each group.\newlineFrom 3d2+2d3d^2 + 2d, factor out dd:\newlined(3d+2)d(3d + 2)\newlineFrom 3d+23d + 2, factor out 11:\newline1(3d+2)1(3d + 2)\newlineNow we have:\newlined(3d+2)+1(3d+2)d(3d + 2) + 1(3d + 2)
  5. Factor out common binomial: Factor out the common binomial factor (3d+2)(3d + 2) from both groups.(3d+2)(3d + 2) is the common factor, so we get:(d+1)(3d+2)(d + 1)(3d + 2)