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Factor.\newline2z2+13z+112z^2 + 13z + 11

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Q. Factor.\newline2z2+13z+112z^2 + 13z + 11
  1. Identify Coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is in the form az2+bz+caz^2 + bz + c, where aa, bb, and cc are constants. For the expression 2z2+13z+112z^2 + 13z + 11, we have:\newlinea=2a = 2\newlineb=13b = 13\newlinec=11c = 11
  2. Find Multiplying Numbers: Find two numbers that multiply to acac (aa times cc) and add up to bb. We need to find two numbers that multiply to (2)(11)=22(2)(11) = 22 and add up to 1313. The numbers that satisfy these conditions are 22 and 1111 because: 2×11=222 \times 11 = 22 2+11=132 + 11 = 13
  3. Rewrite Middle Term: Rewrite the middle term using the two numbers found in the previous step.\newlineWe can express the middle term 13z13z as the sum of 2z2z and 11z11z. This gives us:\newline2z2+13z+11=2z2+2z+11z+112z^2 + 13z + 11 = 2z^2 + 2z + 11z + 11
  4. Factor by Grouping: Factor by grouping.\newlineWe group the terms as follows:\newline(2z2+2z)+(11z+11)(2z^2 + 2z) + (11z + 11)\newlineNow we factor out the common factors from each group:\newline2z(z+1)+11(z+1)2z(z + 1) + 11(z + 1)
  5. Factor out Binomial: Factor out the common binomial.\newlineWe notice that (z+1)(z + 1) is common in both terms, so we factor it out:\newline2z(z+1)+11(z+1)=(2z+11)(z+1)2z(z + 1) + 11(z + 1) = (2z + 11)(z + 1)