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Factor.\newline2t2+9t+72t^2 + 9t + 7

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Q. Factor.\newline2t2+9t+72t^2 + 9t + 7
  1. Identify Variables: Identify aa, bb, and cc in the quadratic expression 2t2+9t+72t^2 + 9t + 7. Compare 2t2+9t+72t^2 + 9t + 7 with ax2+bx+cax^2 + bx + c. a=2a = 2 b=9b = 9 c=7c = 7
  2. Find Multiplying Numbers: Find two numbers that multiply to aca*c (which is 27=142*7=14) and add up to bb (which is 99).\newlineWe need to find two numbers that satisfy these conditions.\newlineAfter checking possible pairs that multiply to 1414 (11 and 1414, 22 and 77), we see that none of these pairs add up to 99.\newlineThis means we cannot factor the quadratic expression by simple inspection or by using integer pairs.
  3. Use Quadratic Formula: Since the quadratic does not factor neatly with integers, we will use the quadratic formula to find the roots of the equation 2t2+9t+7=02t^2 + 9t + 7 = 0.\newlineThe quadratic formula is given by t=b±b24ac2at = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\newlineLet's calculate the discriminant first: b24ac=924(2)(7)=8156=25b^2 - 4ac = 9^2 - 4(2)(7) = 81 - 56 = 25.
  4. Calculate Discriminant: Now we can find the roots using the quadratic formula.\newlinet=9±2522t = \frac{-9 \pm \sqrt{25}}{2\cdot2}\newlinet=9±54t = \frac{-9 \pm 5}{4}\newlineWe have two possible values for tt:\newlinet1=(9+5)4=44=1t_1 = \frac{(-9 + 5)}{4} = \frac{-4}{4} = -1\newlinet2=(95)4=144=3.5t_2 = \frac{(-9 - 5)}{4} = \frac{-14}{4} = -3.5
  5. Find Roots Using Formula: Write the factored form using the roots found.\newlineThe factored form of the quadratic expression is (tt1)(tt2)(t - t_1)(t - t_2).\newlineSubstitute t1t_1 and t2t_2 into the factored form:\newline(t(1))(t(3.5))=(t+1)(t+3.5)(t - (-1))(t - (-3.5)) = (t + 1)(t + 3.5)\newlineHowever, this does not match the original expression's coefficients, which are all integers. We made a mistake in assuming that the quadratic could be factored over the integers. Since the roots are not integers, the quadratic expression cannot be factored over the integers.