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Factor.\newline2t2+13t+112t^2 + 13t + 11

Full solution

Q. Factor.\newline2t2+13t+112t^2 + 13t + 11
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2t2+13t+112t^2 + 13t + 11 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=13b = 13, c=11c = 11
  2. Find suitable numbers: Find two numbers that multiply to aca*c (which is 211=222*11 = 22) and add up to bb (which is 1313).\newlineThe two numbers that satisfy these conditions are 22 and 1111 because 211=222*11 = 22 and 2+11=132+11 = 13.
  3. Rewrite middle term: Rewrite the middle term 13t13t using the two numbers found in Step 22.\newline2t2+13t+112t^2 + 13t + 11 can be rewritten as 2t2+2t+11t+112t^2 + 2t + 11t + 11.
  4. Factor by grouping: Factor by grouping. Group the terms into two pairs and factor out the common factor from each pair.\newlineFrom the first pair 2t2+2t2t^2 + 2t, factor out 2t2t to get 2t(t+1)2t(t + 1).\newlineFrom the second pair 11t+1111t + 11, factor out 1111 to get 11(t+1)11(t + 1).
  5. Write factored form: Write the factored form by combining the common factors.\newlineSince both groups contain the factor (t+1)(t + 1), the factored form is (2t+11)(t+1)(2t + 11)(t + 1).