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Factor.\newline2t2+11t+92t^2 + 11t + 9

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Q. Factor.\newline2t2+11t+92t^2 + 11t + 9
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2t2+11t+92t^2 + 11t + 9. Compare 2t2+11t+92t^2 + 11t + 9 with ax2+bx+cax^2 + bx + c. a=2a = 2 bb00 bb11
  2. Find numbers multiply and add: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (1111).\newlineWe need to find two numbers that multiply to 1818 and add up to 1111.\newlineThe numbers 22 and 99 satisfy these conditions because 29=182*9 = 18 and 2+9=112+9 = 11.
  3. Rewrite middle term: Rewrite the middle term 11t11t using the two numbers found in Step 22.\newlineWe can express 11t11t as the sum of 2t2t and 9t9t.\newlineSo, 2t2+11t+92t^2 + 11t + 9 becomes 2t2+2t+9t+92t^2 + 2t + 9t + 9.
  4. Factor by grouping: Factor by grouping.\newlineFirst, group the terms: 2t2+2t2t^2 + 2t + 9t+99t + 9.\newlineFactor out the common factor from each group.\newlineFrom the first group, we can factor out 2t2t: 2t(t+1)2t(t + 1).\newlineFrom the second group, we can factor out 99: 9(t+1)9(t + 1).
  5. Write factored form: Write the factored form of the expression.\newlineSince both groups contain the factor (t+1)(t + 1), we can factor this out.\newlineThe factored form is (2t+9)(t+1)(2t + 9)(t + 1).