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Factor.\newline2q2+9q+102q^2 + 9q + 10

Full solution

Q. Factor.\newline2q2+9q+102q^2 + 9q + 10
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2q2+9q+102q^2 + 9q + 10 by comparing it with the standard form ax2+bx+cax^2 + bx + c.\newlinea=2a = 2\newlineb=9b = 9\newlinebb00
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 210=202*10 = 20) and add up to bb (which is 99).\newlineThe two numbers that satisfy these conditions are 55 and 44, since 54=205*4 = 20 and 5+4=95+4 = 9.
  3. Rewrite middle term: Rewrite the middle term, 9q9q, using the two numbers found in the previous step.\newline2q2+9q+102q^2 + 9q + 10 can be rewritten as 2q2+5q+4q+102q^2 + 5q + 4q + 10.
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(2q2+5q)+(4q+10)(2q^2 + 5q) + (4q + 10)
  5. Factor out common factor: Factor out the greatest common factor from each group.\newlineFrom the first group, factor out qq: q(2q+5)q(2q + 5)\newlineFrom the second group, factor out 44: 4(2q+5)4(2q + 5)
  6. Final factored form: Since both groups contain the common factor (2q+5)(2q + 5), factor this out.\newlineThe factored form is (q+4)(2q+5)(q + 4)(2q + 5).