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Factor.\newline2q2+11q+92q^2 + 11q + 9

Full solution

Q. Factor.\newline2q2+11q+92q^2 + 11q + 9
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2q2+11q+92q^2 + 11q + 9 by comparing it to the standard form ax2+bx+cax^2 + bx + c.
    a=2a = 2, b=11b = 11, c=9c = 9
  2. Find two numbers: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (1111).\newlineThe numbers that satisfy these conditions are 22 and 99 because 29=182*9 = 18 and 2+9=112+9 = 11.
  3. Rewrite middle term: Rewrite the middle term 11q11q using the two numbers found in the previous step.\newline2q2+11q+92q^2 + 11q + 9 can be rewritten as 2q2+2q+9q+92q^2 + 2q + 9q + 9.
  4. Factor by grouping: Factor by grouping. Group the first two terms and the last two terms.\newline(2q2+2q)+(9q+9)(2q^2 + 2q) + (9q + 9)
  5. Factor out common factor: Factor out the greatest common factor from each group. 2q(q+1)+9(q+1)2q(q + 1) + 9(q + 1)
  6. Final factorization: Since both groups contain the common factor (q+1)(q + 1), factor this out.(2q+9)(q+1)(2q + 9)(q + 1)