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Factor.\newline2j2+9j+92j^2 + 9j + 9

Full solution

Q. Factor.\newline2j2+9j+92j^2 + 9j + 9
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2j2+9j+92j^2 + 9j + 9 by comparing it to the standard form ax2+bx+cax^2 + bx + c.
    a=2a = 2, b=9b = 9, c=9c = 9
  2. Find two numbers: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (99).\newlineThe two numbers that satisfy these conditions are 33 and 66, since 36=183*6 = 18 and 3+6=93+6 = 9.
  3. Rewrite middle term: Rewrite the middle term 9j9j using the two numbers found in the previous step.\newline2j2+9j+92j^2 + 9j + 9 can be rewritten as 2j2+3j+6j+92j^2 + 3j + 6j + 9.
  4. Factor by grouping: Factor by grouping. Group the first two terms and the last two terms.\newline(2j2+3j)+(6j+9)(2j^2 + 3j) + (6j + 9)
  5. Factor out common factor: Factor out the greatest common factor from each group.\newlinej(2j+3)+3(2j+3)j(2j + 3) + 3(2j + 3)
  6. Final factored form: Since both groups contain the common factor (2j+3)(2j + 3), factor this out.(j+3)(2j+3)(j + 3)(2j + 3) is the factored form of the quadratic expression.