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Factor.\newline10n314n2+5n710n^3 - 14n^2 + 5n - 7

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Q. Factor.\newline10n314n2+5n710n^3 - 14n^2 + 5n - 7
  1. Identify Common Factors: Look for common factors in pairs of terms.\newlineWe can try to factor by grouping, which involves combining terms that have common factors. We'll look at the first two terms and the last two terms separately.
  2. Factor First Two Terms: Factor out the common factor from the first two terms.\newlineThe first two terms are 10n310n^3 and 14n2-14n^2. The greatest common factor (GCF) of these terms is 2n22n^2.\newline10n314n2=2n2(5n7)10n^3 - 14n^2 = 2n^2(5n - 7)
  3. Factor Last Two Terms: Factor out the common factor from the last two terms.\newlineThe last two terms are 5n5n and 7-7. These terms do not have a common numerical factor other than 11, but we can still group them as a single term.\newline5n7=1(5n7)5n - 7 = 1(5n - 7)
  4. Combine Groups: Write the expression as the sum of the two groups.\newlineNow we have factored the first two terms and the last two terms, we can write the expression as:\newline2n2(5n7)+1(5n7)2n^2(5n - 7) + 1(5n - 7)
  5. Factor Out Binomial: Factor out the common binomial factor.\newlineWe can see that the binomial (5n7)(5n - 7) is common in both groups, so we can factor it out.\newline2n2(5n7)+1(5n7)=(5n7)(2n2+1)2n^2(5n - 7) + 1(5n - 7) = (5n - 7)(2n^2 + 1)
  6. Verify Factorization: Verify the factored form by expanding it to see if it matches the original expression.\newline(5n7)(2n2+1)=5n(2n2)+5n(1)7(2n2)7(1)(5n - 7)(2n^2 + 1) = 5n(2n^2) + 5n(1) - 7(2n^2) - 7(1)\newline=10n3+5n14n27= 10n^3 + 5n - 14n^2 - 7\newline=10n314n2+5n7= 10n^3 - 14n^2 + 5n - 7\newlineThis matches the original expression, so our factorization is correct.