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f(x)=xexf(x)=xe^{x}\newlinef(x)=?f'(x) =?

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Q. f(x)=xexf(x)=xe^{x}\newlinef(x)=?f'(x) =?
  1. Identify Functions: Let's identify the two functions that we are dealing with in the product. The first function is xx, and the second function is exe^x. We will need to use the product rule to find the derivative of f(x)=xexf(x) = xe^x, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function.
  2. Derivative of xx: The derivative of the first function, which is xx, is 11.
  3. Derivative of exe^x: The derivative of the second function, which is exe^x, is exe^x because the derivative of exe^x with respect to xx is exe^x.
  4. Apply Product Rule: Now we apply the product rule. According to the product rule, the derivative of f(x)=xexf(x) = xe^x is f(x)=(derivative of x)(ex)+(x)(derivative of ex)f'(x) = (\text{derivative of } x) \cdot (e^x) + (x) \cdot (\text{derivative of } e^x). Substituting the derivatives we found in the previous steps, we get f(x)=1ex+xexf'(x) = 1 \cdot e^x + x \cdot e^x.
  5. Simplify Expression: Simplify the expression by combining like terms. Since both terms have a factor of exe^x, we can factor it out to get f(x)=ex(1+x)f'(x) = e^x(1 + x).

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