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f(x)=(x^(2)+x)^(10)(2x+1)

22. f(x)=(x2+x)10(2x+1) f(x)=\left(x^{2}+x\right)^{10}(2 x+1)

Full solution

Q. 22. f(x)=(x2+x)10(2x+1) f(x)=\left(x^{2}+x\right)^{10}(2 x+1)
  1. Identify Function Components: Identify the function components to apply the product rule for differentiation: f(x)=u(x)v(x)f(x) = u(x)v(x), where u(x)=(x2+x)10u(x) = (x^2 + x)^{10} and v(x)=(2x+1)v(x) = (2x + 1).
  2. Differentiate u(x)u(x): Differentiate u(x)=(x2+x)10u(x) = (x^2 + x)^{10} using the chain rule: u(x)=10(x2+x)9(2x+1)u'(x) = 10(x^2 + x)^9 \cdot (2x + 1).

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