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f(x)={[x^(2)-8," for ",x!=2],[4," for ",x=2]:} Find f(4) Answer:

f(x)={x2−8 for x≠24 for x=2 f(x)=\left\{\begin{array}{lll} x^{2}-8 & \text { for } & x \neq 2 \\ 4 & \text { for } & x=2 \end{array}\right. \newlineFind f(4) f(4) \newlineAnswer:\newline

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Q. f(x)={x2−8 for x≠24 for x=2 f(x)=\left\{\begin{array}{lll} x^{2}-8 & \text { for } & x \neq 2 \\ 4 & \text { for } & x=2 \end{array}\right. \newlineFind f(4) f(4) \newlineAnswer:\newline
  1. Identify Part for x=4x = 4: Identify which part of the piecewise function to use for x=4x = 4.\newlineThe function f(x)f(x) is defined as:\newlinef(x)=x2−8f(x) = x^2 - 8 for x≠2x \neq 2\newlinef(x)=4f(x) = 4 for x=2x = 2\newlineSince we are looking for f(4)f(4), we use the first part of the function because 4≠24 \neq 2.
  2. Substitute x=4x = 4: Substitute x=4x = 4 into the first part of the function.\newlinef(4)=42−8f(4) = 4^2 - 8\newlineCalculate the value.\newlinef(4)=16−8f(4) = 16 - 8\newlinef(4)=8f(4) = 8

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