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f(x)=72ln(x)f(x) = 72 \ln(x) for x<0x < 0 for >0\infty > 0 Find limx+1f(x)\lim_{x \to +1} f(x). Choose 11 answer:\newline(A) 00\newline(B) 11\newline(C) ee\newline(D) The limit doesn't exist.

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Q. f(x)=72ln(x)f(x) = 72 \ln(x) for x<0x < 0 for >0\infty > 0 Find limx+1f(x)\lim_{x \to +1} f(x). Choose 11 answer:\newline(A) 00\newline(B) 11\newline(C) ee\newline(D) The limit doesn't exist.
  1. Understand given function: First, we need to understand the function given. The function f(x)=72ln(x)f(x) = 72 \ln(x) is only defined for x<0x < 0, and it's \infty for x>0x > 0. We're looking for the limit as xx approaches 11 from the left, which means we're interested in the behavior of the function just before xx reaches 11.
  2. Approaching 11 from left: Since we're approaching 11 from the left, we're actually looking at values of xx that are less than 11. However, the function f(x)=72ln(x)f(x) = 72 \ln(x) is not defined for x0x \geq 0, so we can't use this part of the function to find the limit as xx approaches 11 from the left.
  3. Function behavior near boundary: The other part of the function says that f(x)f(x) is \infty for x>0x > 0. As we approach 11 from the left, we're getting closer to the boundary where the function switches to \infty. But since we never actually reach x>0x > 0 from the left side, we can't say the limit is \infty.
  4. Limit does not exist: Therefore, since the function is not defined for x0x \geq 0, and we're approaching 11 from the left, the limit does not exist because there's no value of f(x)f(x) that xx can approach as it gets close to 11 from the left side.

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