Q. f(x)=72ln(x) for x<0 for ∞>0 Find limx→+1f(x). Choose 1 answer:(A) 0(B) 1(C) e(D) The limit doesn't exist.
Understand given function: First, we need to understand the function given. The function f(x)=72ln(x) is only defined for x<0, and it's ∞ for x>0. We're looking for the limit as x approaches 1 from the left, which means we're interested in the behavior of the function just before x reaches 1.
Approaching 1 from left: Since we're approaching 1 from the left, we're actually looking at values of x that are less than 1. However, the function f(x)=72ln(x) is not defined for x≥0, so we can't use this part of the function to find the limit as x approaches 1 from the left.
Function behavior near boundary: The other part of the function says that f(x) is ∞ for x>0. As we approach 1 from the left, we're getting closer to the boundary where the function switches to ∞. But since we never actually reach x>0 from the left side, we can't say the limit is ∞.
Limit does not exist: Therefore, since the function is not defined for x≥0, and we're approaching 1 from the left, the limit does not exist because there's no value of f(x) that x can approach as it gets close to 1 from the left side.
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