f(x)=(1)/(8x+3) g(x)=12-5x Write f(g(x)) as an expression in terms of x. f(g(x))=

Find g(x): First, we need to find the expression for g(x), which is given as g(x) = 12 - 5x. Substitute g(x) into f(x): Next, we will substitute the expression for g(x) into the function f(x), where f(x) = (1)/(8x+3). So, f(g(x)) becomes f(12 - 5x). Perform substitution in f(x): Now, we substitute 12 - 5x into the function f(x) in place of x, which gives us f(g(x)) = (1)/(8(12 - 5x) + 3). Perform multiplication: We then perform the multiplication inside the parentheses: 8 * (12 - 5x) = 96 - 40x. Add 3: Finally, we add 3 to the result of the multiplication to get the expression for f(g(x)): f(g(x)) = (1)/(96 - 40x + 3). Simplify expression: Simplify the expression by combining like terms in the denominator: f(g(x)) = (1)/(99 - 40x).

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f(x)=(1)/(8x+3)

g(x)=12-5x
Write
f(g(x)) as an expression in terms of
x.

f(g(x))=

$f(x)=\frac{1}{8 x+3}$ $\newline$ $g(x)=12-5 x$ $\newline$ Write $f(g(x))$ as an expression in terms of $x$ . $\newline$ $f(g(x))=$

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

f(x)=\frac{1}{8 x+3}

\newline

g(x)=12-5 x

\newline

Write

f(g(x))

as an expression in terms of

x

\newline

f(g(x))=

Find $g(x)$ : First, we need to find the expression for $g(x)$ , which is given as $g(x) = 12 - 5x$ .
Substitute $g(x)$ into $f(x)$ : Next, we will substitute the expression for $g(x)$ into the function $f(x)$ , where $f(x) = \frac{1}{8x+3}$ . So, $f(g(x))$ becomes $f(12 - 5x)$ .
Perform substitution in $f(x)$ : Now, we substitute $12 - 5x$ into the function $f(x)$ in place of $x$ , which gives us $f(g(x)) = \frac{1}{8(12 - 5x) + 3}$ .
Perform multiplication: We then perform the multiplication inside the parentheses: $8 \times (12 - 5x) = 96 - 40x$ .
Add $3$ : Finally, we add $3$ to the result of the multiplication to get the expression for $f(g(x))$ : $f(g(x)) = \frac{1}{96 - 40x + 3}$ .
Simplify expression: Simplify the expression by combining like terms in the denominator: $f(g(x)) = \frac{1}{99 - 40x}$ .