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Let’s check out your problem:
f
(
t
)
=
80
(
4
)
t
f(t)=80(4)^{t}
f
(
t
)
=
80
(
4
)
t
\newline
Which of the following is an equivalent form of the function
f
f
f
in which the base of the exponent is
2
2
2
?
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Math Problems
Algebra 1
Simplify radical expressions with variables
Full solution
Q.
f
(
t
)
=
80
(
4
)
t
f(t)=80(4)^{t}
f
(
t
)
=
80
(
4
)
t
\newline
Which of the following is an equivalent form of the function
f
f
f
in which the base of the exponent is
2
2
2
?
Express as Power of
2
2
2
:
First, we need to express
4
4
4
as a power of
2
2
2
because
4
4
4
is
2
2
2
squared, or
2
2
2^2
2
2
.
Substitute in
f
(
t
)
f(t)
f
(
t
)
:
Now, we substitute
4
4
4
with
2
2
2^2
2
2
in the function
f
(
t
)
f(t)
f
(
t
)
. So,
f
(
t
)
f(t)
f
(
t
)
becomes
80
(
2
2
)
t
80(2^2)^t
80
(
2
2
)
t
.
Apply Power Rule:
Next, we apply the power of a power rule which states
(
a
b
)
c
=
a
(
b
∗
c
)
(a^b)^c = a^{(b*c)}
(
a
b
)
c
=
a
(
b
∗
c
)
.
\newline
So,
(
2
2
)
t
(2^2)^t
(
2
2
)
t
becomes
2
(
2
t
)
2^{(2t)}
2
(
2
t
)
.
Rewrite with New Base:
Now, we rewrite the function
f
(
t
)
f(t)
f
(
t
)
with the new base of the exponent.
f
(
t
)
=
80
×
2
2
t
.
f(t) = 80 \times 2^{2t}.
f
(
t
)
=
80
×
2
2
t
.
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