Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

F=[[5],[0],[4]]" and "A=[[-1,1]] Let H=FA. Find H. H=[]

F=[504] and A=[−11] \mathrm{F}=\left[\begin{array}{l} 5 \\ 0 \\ 4 \end{array}\right] \text { and } \mathrm{A}=\left[\begin{array}{ll} -1 & 1 \end{array}\right] \newlineLet H=FA \mathrm{H}=\mathrm{FA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 1right chevron icon
Unions and intersections of setsright chevron icon

Full solution

Q. F=[504] and A=[−11] \mathrm{F}=\left[\begin{array}{l} 5 \\ 0 \\ 4 \end{array}\right] \text { and } \mathrm{A}=\left[\begin{array}{ll} -1 & 1 \end{array}\right] \newlineLet H=FA \mathrm{H}=\mathrm{FA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
  1. Understand matrix multiplication: Understand matrix multiplication. Matrix multiplication involves taking the rows of the first matrix FF and multiplying them by the columns of the second matrix AA, then summing the products to get the entries of the resulting matrix HH.
  2. Identify matrix dimensions: Identify the dimensions of the matrices.\newlineMatrix FF is a 3×13 \times 1 matrix and matrix AA is a 1×21 \times 2 matrix. The resulting matrix HH will have the dimensions of the outer dimensions, which is 3×23 \times 2.
  3. Multiply first row of F: Multiply the first row of FF by the only column of AA. The first row of FF is [5][5], and the only column of AA is [−1,1][-1, 1]. Multiplying these, we get: 5×−1=−55 \times -1 = -5 5×1=55 \times 1 = 5 So the first row of HH will be [−5,5][-5, 5].
  4. Multiply second row of F: Multiply the second row of F by the only column of A.\newlineThe second row of F is [0][0], and the only column of A is [−1,1][-1, 1]. Multiplying these, we get:\newline0×−1=00 \times -1 = 0\newline0×1=00 \times 1 = 0\newlineSo the second row of H will be [0,0][0, 0].
  5. Multiply third row of F: Multiply the third row of FF by the only column of AA. The third row of FF is [4][4], and the only column of AA is [−1,1][-1, 1]. Multiplying these, we get: 4×−1=−44 \times -1 = -4 4×1=44 \times 1 = 4 So the third row of HH will be [−4,4][-4, 4].
  6. Combine results for matrix HH: Combine the results to form the matrix HH. Combining the results from steps 33, 44, and 55, we get the matrix HH: H=[−55 00 −44]H = \left[\begin{array}{cc} -5 & 5 \ 0 & 0 \ -4 & 4 \end{array}\right]

More problems from Unions and intersections of sets

Question
z=−24−12.7i z=-24-12.7 i \newlineWhat are the real and imaginary parts of z z ?\newlineChoose 11 answer:\newline(A)\newlineRe⁡(z)=−24 and Im⁡(z)=−12.7 \begin{array}{l} \operatorname{Re}(z)=-24 \text { and } \\ \operatorname{Im}(z)=-12.7 \end{array} \newline(B)\newlineRe⁡(z)=−24 and Im⁡(z)=−12.7i \begin{array}{l} \operatorname{Re}(z)=-24 \text { and } \\ \operatorname{Im}(z)=-12.7 i \end{array} \newline(C)\newlineRe⁡(z)=−12.7 and Im⁡(z)=−24 \begin{array}{l} \operatorname{Re}(z)=-12.7 \text { and } \\ \operatorname{Im}(z)=-24 \end{array} \newline(D)\newlineRe⁡(z)=−12.7i and Im⁡(z)=−24 \begin{array}{l} \operatorname{Re}(z)=-12.7 i \text { and } \\ \operatorname{Im}(z)=-24 \end{array}
Get tutor helpright-arrow

Posted 3 months ago

Question
z=77−27.8i z=77-27.8 i \newlineWhat are the real and imaginary parts of z z ?\newlineChoose 11 answer:\newline(A)\newlineRe⁡(z)=77 and Im⁡(z)=−27.8 \begin{array}{l} \operatorname{Re}(z)=77 \text { and } \\ \operatorname{Im}(z)=-27.8 \end{array} \newline(B)\newlineRe⁡(z)=−27.8i and Im⁡(z)=77 \begin{array}{l} \operatorname{Re}(z)=-27.8 i \text { and } \\ \operatorname{Im}(z)=77 \end{array} \newline(C)\newlineRe⁡(z)=−27.8 and Im⁡(z)=77 \begin{array}{l} \operatorname{Re}(z)=-27.8 \text { and } \\ \operatorname{Im}(z)=77 \end{array} \newline(D)\newlineRe⁡(z)=77 and Im⁡(z)=−27.8i \begin{array}{l} \operatorname{Re}(z)=77 \text { and } \\ \operatorname{Im}(z)=-27.8 i \end{array}
Get tutor helpright-arrow

Posted 3 months ago

Question
z=−16i−92.3 z=-16 i-92.3 \newlineWhat are the real and imaginary parts of z z ?\newlineChoose 11 answer:\newline(A)\newlineRe⁡(z)=−92.3 and Im⁡(z)=−16i \begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 i \end{array} \newline(B)\newlineRe⁡(z)=−92.3 and Im⁡(z)=−16 \begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 \end{array} \newline(C)\newlineRe⁡(z)=−16i and Im⁡(z)=−92.3 \begin{array}{l} \operatorname{Re}(z)=-16 i \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array} \newline(D)\newlineRe⁡(z)=−16 and Im⁡(z)=−92.3 \begin{array}{l} \operatorname{Re}(z)=-16 \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array}
Get tutor helpright-arrow

Posted 3 months ago

Question
x2+8x+6=0 x^{2}+8 x+6=0 \newlineWhat are the solutions to the given equation?\newlineChoose 11 answer:\newline(A)\newlinex=−8−10 and x=−8+10 \begin{array}{l} x=-8-\sqrt{10} \text { and } \\ x=-8+\sqrt{10} \end{array} \newline(B)\newlinex=−8−7 and x=−8+7 \begin{array}{l} x=-8-\sqrt{7} \text { and } \\ x=-8+\sqrt{7} \end{array} \newline(C)\newlinex=−4−10 and x=−4+10 \begin{array}{l} x=-4-\sqrt{10} \text { and } \\ x=-4+\sqrt{10} \end{array} \newline(D)\newlinex=−4−7 and x=−4+7 \begin{array}{l} x=-4-\sqrt{7} \text { and } \\ x=-4+\sqrt{7} \end{array}
Get tutor helpright-arrow

Posted 3 months ago

Question
If x2+6x−5=0 x^{2}+6 x-5=0 , what are the values of x x ?\newlineChoose 11 answer:\newline(A) −3−14 -3-\sqrt{14} and −3+14 -3+\sqrt{14} \newline(B) 3−14 3-\sqrt{14} and 3+14 3+\sqrt{14} \newline(C) −1-1 and −5-5\newline(D) 11 and 55
Get tutor helpright-arrow

Posted 3 months ago

Question
Consider the expression 4(8x+5) 4(8 x+5) .\newlineComplete 22 descriptions of the parts of the expression.\newline11. The entire expression is the product of □\square. \newline22. On its own, (8x+5) (8 x+5) is a sum with □\square.
Get tutor helpright-arrow

Posted 3 months ago

Question
Evaluate f−g+(−2) f-g+(-2) where f=−3.005 f=-3.005 and g=4.7 g=4.7 .
Get tutor helpright-arrow

Posted 3 months ago

Question
Evaluate −a+(−b) -a+(-b) where a=6.05 a=6.05 and b=3.611 b=3.611 .
Get tutor helpright-arrow

Posted 3 months ago

Question
E=[−1−2−2−1] E=\left[\begin{array}{ll}-1 & -2 \\ -2 & -1\end{array}\right] and A=[202−1]. A=\left[\begin{array}{rr} 2 & 0 \\ 2 & -1 \end{array}\right] . \newlineLet H=EA \mathrm{H}=\mathrm{EA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
Get tutor helpright-arrow

Posted 3 months ago

Question
B=[5−2−15] \mathbf{B}=\left[\begin{array}{rr}5 & -2 \\ -1 & 5\end{array}\right] and A=[2002] \mathrm{A}=\left[\begin{array}{ll}2 & 0 \\ 0 & 2\end{array}\right] .\newlineLet H=BA \mathrm{H}=\mathrm{BA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
Get tutor helpright-arrow

Posted 3 months ago

View all (20)