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Extra Questions: A, B&C start a game of Preparing bead necklaces. A takes 12 minutes, B takes 18 minutes & c.m C takes 24 minutes to prepare one necklace Affer how much dime all the three children stast to prepare a new necklace simultaneously

Extra Questions:\newline11. A, B&C B \& C start a game of Preparing bead necklaces. A A takes 1212 minutes, B B takes 1818 minutes \&\newlinec.m C takes 2424 minutes to prepare one necklace Affer how much dime all the three children stast to prepare a new necklace simultaneously

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Q. Extra Questions:\newline11. A, B&C B \& C start a game of Preparing bead necklaces. A A takes 1212 minutes, B B takes 1818 minutes \&\newlinec.m C takes 2424 minutes to prepare one necklace Affer how much dime all the three children stast to prepare a new necklace simultaneously
  1. Identify Time Taken: Identify the time taken by AA, BB, and CC to prepare one necklace each. AA takes 1212 minutes, BB takes 1818 minutes, and CC takes 2424 minutes.
  2. Find LCM: Find the least common multiple (LCM) of the times taken by A, B, and C to determine when they will all finish a necklace at the same time and start a new one together. Calculate LCM of 1212, 1818, and 2424.
  3. Break Down Factors: Break down each time into its prime factors: 12=22×312 = 2^2 \times 3, 18=2×3218 = 2 \times 3^2, and 24=23×324 = 2^3 \times 3.
  4. Calculate LCM: The LCM is found by taking the highest power of each prime that appears in the factorization. LCM=23×32\text{LCM} = 2^3 \times 3^2.
  5. Calculate LCM: The LCM is found by taking the highest power of each prime that appears in the factorization. LCM=23×32\text{LCM} = 2^3 \times 3^2. Calculate the LCM: 23=82^3 = 8 and 32=93^2 = 9, so LCM=8×9=72\text{LCM} = 8 \times 9 = 72 minutes.

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