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Express as a single logarithm.\newline3loga3+7loga53\log_{a}3+7\log_{a}5

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Q. Express as a single logarithm.\newline3loga3+7loga53\log_{a}3+7\log_{a}5
  1. Identify Properties: Identify the properties of logarithms that can be used to combine the terms.\newlineThe given expression is 3loga3+7loga53\log_{a}3 + 7\log_{a}5. We can use the power rule of logarithms to move the coefficients in front of the logarithms to the exponent position inside the logarithms.\newlinePower Rule: nlogb(x)=logb(xn)n\log_{b}(x) = \log_{b}(x^n)
  2. Apply Power Rule: Apply the power rule to each term in the expression.\newlineUsing the power rule, we rewrite each term:\newline3loga3=loga(33)3\log_{a}3 = \log_{a}(3^{3})\newline7loga5=loga(57)7\log_{a}5 = \log_{a}(5^{7})
  3. Calculate Exponents: Calculate the exponents.\newlineCalculate 333^3 and 575^7:\newline33=273^3 = 27\newline57=781255^7 = 78125\newlineNow the expression is loga(27)+loga(78125)\log_{a}(27) + \log_{a}(78125).
  4. Combine Logarithms: Combine the logarithms using the product property.\newlineNow that we have two logarithms with the same base and no coefficients in front, we can combine them using the product property.\newlineProduct Property: logb(x)+logb(y)=logb(xy)\log_b(x) + \log_b(y) = \log_b(xy)\newlineCombine the logarithms:\newlineloga(27)+loga(78125)=loga(27×78125)\log_{a}(27) + \log_{a}(78125) = \log_{a}(27 \times 78125)
  5. Calculate Product: Calculate the product inside the logarithm.\newlineMultiply 2727 by 7812578125:\newline27×78125=210937527 \times 78125 = 2109375\newlineNow the expression is loga(2109375)\log_{a}(2109375).

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