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Express as a function of a DIFFERENT angle, 
0^(@) <= theta < 360^(@).

sin(332^(@))

sin(◻^(@))

Express as a function of a DIFFERENT angle, 0θ<360 0^{\circ} \leq \theta<360^{\circ} .\newlinesin(332) \sin \left(332^{\circ}\right) \newlinesin() \sin \left(\square^{\circ}\right)

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Q. Express as a function of a DIFFERENT angle, 0θ<360 0^{\circ} \leq \theta<360^{\circ} .\newlinesin(332) \sin \left(332^{\circ}\right) \newlinesin() \sin \left(\square^{\circ}\right)
  1. Find Equivalent Angle: We need to find an equivalent angle for 332332^\circ that falls within the first or second quadrant (00^\circ to 180180^\circ) to express sin(332)\sin(332^\circ) as a function of a different angle. We can use the fact that sine is a periodic function with a period of 360360^\circ, and that sin(θ)=sin(360θ)\sin(\theta) = \sin(360^\circ - \theta) for angles in the fourth quadrant.
  2. Calculate Reference Angle: Calculate the reference angle for 332332^\circ. The reference angle is the acute angle formed by the terminal side of the angle and the x-axis. For an angle in the fourth quadrant, the reference angle is 360θ360^\circ - \theta.
  3. Substitute into Formula: Substitute 332332^\circ into the reference angle formula: reference angle = 360332=28360^\circ - 332^\circ = 28^\circ.
  4. Express as sin(28°)\sin(28°): Now we can express sin(332°)\sin(332°) as sin(360°28°)\sin(360° - 28°), which is equivalent to sin(28°)\sin(28°) because sine is a co-function of its complement.
  5. Final Result: Since 28°28° is in the first quadrant, where sine is positive, we can say that sin(332°)=sin(28°)\sin(332°) = \sin(28°).

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