Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Exercise 2: Check your understanding of the t-test of independent means:

A physical education teacher compared the scores of boys and girls in basketball and obtained the following data: Group (Boys) 9, 7, 5, 10, 9
Group (Girls) 6, 5, 7, 3, 4

Exercise 22: Check your understanding of the t-test of independent means:\newline11. A physical education teacher compared the scores of boys and girls in basketball and obtained the following data: Group (Boys) 99, 77, 55, 1010, 99\newlineGroup (Girls) 66, 55, 77, 33, 44

Full solution

Q. Exercise 22: Check your understanding of the t-test of independent means:\newline11. A physical education teacher compared the scores of boys and girls in basketball and obtained the following data: Group (Boys) 99, 77, 55, 1010, 99\newlineGroup (Girls) 66, 55, 77, 33, 44
  1. Calculate Mean: Calculate the mean for each group.\newlineBoys: (9+7+5+10+9)/5=8(9 + 7 + 5 + 10 + 9) / 5 = 8\newlineGirls: (6+5+7+3+4)/5=5(6 + 5 + 7 + 3 + 4) / 5 = 5
  2. Calculate Variance: Calculate the variance for each group.\newlineBoys: [(98)2+(78)2+(58)2+(108)2+(98)2]/4=4.5[(9-8)^2 + (7-8)^2 + (5-8)^2 + (10-8)^2 + (9-8)^2] / 4 = 4.5\newlineGirls: [(65)2+(55)2+(75)2+(35)2+(45)2]/4=2.5[(6-5)^2 + (5-5)^2 + (7-5)^2 + (3-5)^2 + (4-5)^2] / 4 = 2.5
  3. Calculate Standard Error: Calculate the standard error of the difference between the means. SE=(4.55)+(2.55)=1.4=1.183SE = \sqrt{(\frac{4.5}{5}) + (\frac{2.5}{5})} = \sqrt{1.4} = 1.183
  4. Calculate t-value: Calculate the t-value.\newlinet=851.183=2.534t = \frac{8 - 5}{1.183} = 2.534

More problems from Find the magnitude of a three-dimensional vector