Q. Example 15.12Find the truth set of43(x+1)+1≤21(x−2)+5llustrate your result on the number line.
Write Inequality: Write down the given inequality.(43)(x+1)+1≤(21)(x−2)+5
Clear Fractions: Clear the fractions by finding a common denominator, which in this case is 4. Multiply every term by 4 to eliminate the fractions.4×(43)(x+1)+4×1≤4×(21)(x−2)+4×5
Simplify Equation: Simplify the equation by performing the multiplication. 3(x+1)+4≤2(x−2)+20
Distribute Multiplication: Distribute the multiplication over addition on both sides of the inequality. 3x+3+4≤2x−4+20
Combine Like Terms: Combine like terms on both sides of the inequality. 3x+7≤2x+16
Isolate Variable Term: Isolate the variable term on one side of the inequality by subtracting 2x from both sides.3x−2x+7≤2x−2x+16
Simplify Inequality: Simplify the inequality after subtracting. x+7≤16
Isolate x: Isolate x by subtracting 7 from both sides of the inequality.x+7−7≤16−7
Illustrate on Number Line: Simplify the inequality to find the solution for x.x≤9
Illustrate on Number Line: Simplify the inequality to find the solution for x.x≤9Illustrate the result on the number line. The solution set includes all numbers less than or equal to 9. This can be represented on the number line with a closed circle at 9 and a line extending to the left, indicating all numbers less than or equal to 9 are included in the truth set.
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