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Every chemical element goes through natural exponential decay, which means that over time its atoms fall apart. The speed of each element's decay is described by its half-life, which is the amount of time it takes for the number of radioactive atoms of this element to be reduced by half. The half-life of the isotope dubnium263-263 is 2929 seconds. A sample of dubnium263-263 was first measured to have 10241024 atoms. After tt seconds, there were only 3232 atoms of this isotope remaining- Write an equation in terms of tt that models the situation.

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Q. Every chemical element goes through natural exponential decay, which means that over time its atoms fall apart. The speed of each element's decay is described by its half-life, which is the amount of time it takes for the number of radioactive atoms of this element to be reduced by half. The half-life of the isotope dubnium263-263 is 2929 seconds. A sample of dubnium263-263 was first measured to have 10241024 atoms. After tt seconds, there were only 3232 atoms of this isotope remaining- Write an equation in terms of tt that models the situation.
  1. Identify Initial Amount: Identify the initial amount of dubnium263-263 and the remaining amount after tt seconds. Use the half-life to set up the decay formula.\newlineInitial amount (N0N_0) = 10241024 atoms, Remaining amount (NN) = 3232 atoms, Half-life (t1/2t_{1/2}) = 2929 seconds.
  2. Use Decay Formula: Use the exponential decay formula N=N0×(1/2)t/t1/2N = N_0 \times (1/2)^{t/t_{1/2}}. Substitute the known values to find tt.32=1024×(1/2)t/2932 = 1024 \times (1/2)^{t/29}
  3. Simplify Equation: Simplify the equation by dividing both sides by 10241024. \newline321024=(12)t29\frac{32}{1024} = \left(\frac{1}{2}\right)^{\frac{t}{29}}
  4. Calculate 32/102432/1024: Calculate 32/102432/1024.\newline32/1024=1/3232/1024 = 1/32
  5. Recognize Base: Recognize that 132\frac{1}{32} is 252^{-5}. Rewrite the equation using this base.\newline25=(12)t292^{-5} = \left(\frac{1}{2}\right)^{\frac{t}{29}}
  6. Convert Equation: Convert the equation to have the same base for easier comparison.\newline25=2t292^{-5} = 2^{-\frac{t}{29}}
  7. Equate Exponents: Equate the exponents since the bases are the same.\newline5=t29-5 = -\frac{t}{29}
  8. Solve for tt: Solve for tt by multiplying both sides by 29-29.t=145t = 145

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