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Evaluate the integral.

int xe^(2x)dx
Answer:

Evaluate the integral.\newlinexe2xdx \int x e^{2 x} d x \newlineAnswer:

Full solution

Q. Evaluate the integral.\newlinexe2xdx \int x e^{2 x} d x \newlineAnswer:
  1. Choose uu and dvdv: To solve the integral of xe2xxe^{2x} with respect to xx, we will use integration by parts, which is given by the formula udv=uvvdu\int u\, dv = uv - \int v\, du, where uu and dvdv are parts of the integrand that we choose.
  2. Apply integration by parts: Let's choose u=xu = x (which will be differentiated) and dv=e2xdxdv = e^{2x}dx (which will be integrated). Differentiating uu gives us du=dxdu = dx, and integrating dvdv gives us v=12e2xv = \frac{1}{2}e^{2x}.
  3. Integrate dv: Now we apply the integration by parts formula: xe2xdx=uvvdu\int x e^{2x} dx = uv - \int v du. Substituting the chosen parts, we get $\int x e^{\(2\)x} dx = x \left(\frac{\(1\)}{\(2\)}\right)e^{\(2\)x} - \int \left(\frac{\(1\)}{\(2\)}\right)e^{\(2\)x} dx.
  4. Substitute back: Next, we integrate \((1/2)e^{2x}\) with respect to \(x\), which gives us \((1/2)\cdot(1/2)e^{2x} = (1/4)e^{2x}\).
  5. Final result: Substituting this back into our equation, we have \(\int x e^{2x} dx = \left(\frac{1}{2}\right) x e^{2x} - \left(\frac{1}{4}\right) e^{2x} + C\), where \(C\) is the constant of integration.
  6. Final result: Substituting this back into our equation, we have \(\int xe^{2x}\,dx = \frac{1}{2}xe^{2x} - \frac{1}{4}e^{2x} + C\), where \(C\) is the constant of integration.Therefore, the integral of \(xe^{2x}\) with respect to \(x\) is \(\frac{1}{2}xe^{2x} - \frac{1}{4}e^{2x} + C\).