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Let’s check out your problem:
Evaluate the integral.
\newline
∫
p
(
p
+
4
)
5
d
p
\int p(p+4)^{5} d p
∫
p
(
p
+
4
)
5
d
p
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Math Problems
Calculus
Find indefinite integrals using the substitution and by parts
Full solution
Q.
Evaluate the integral.
\newline
∫
p
(
p
+
4
)
5
d
p
\int p(p+4)^{5} d p
∫
p
(
p
+
4
)
5
d
p
Substitution:
Let's do a substitution. Let
u
=
p
+
4
u = p + 4
u
=
p
+
4
, then
d
u
=
d
p
du = dp
d
u
=
d
p
.
Change in terms of u:
Now we need to change
p
p
p
in terms of
u
u
u
. Since
u
=
p
+
4
u = p + 4
u
=
p
+
4
,
p
=
u
−
4
p = u - 4
p
=
u
−
4
.
Substitute and expand:
Substitute
p
p
p
and
d
p
dp
d
p
into the integral:
∫
(
u
−
4
)
u
5
d
u
\int (u - 4)u^5 \, du
∫
(
u
−
4
)
u
5
d
u
.
Integrate terms:
Expand the integrand:
∫
(
u
6
−
4
u
5
)
d
u
\int (u^6 - 4u^5) \, du
∫
(
u
6
−
4
u
5
)
d
u
.
Simplify integral:
Integrate term by term:
(
u
7
7
)
−
(
4
u
6
6
)
+
C
(\frac{u^7}{7}) - (\frac{4u^6}{6}) + C
(
7
u
7
)
−
(
6
4
u
6
)
+
C
.
Substitute back u:
Simplify the integral:
u
7
7
\frac{u^7}{7}
7
u
7
-
2
u
6
3
\frac{2u^6}{3}
3
2
u
6
+
C
C
C
.
Substitute back
u
u
u
:
Simplify the integral:
u
7
7
\frac{u^7}{7}
7
u
7
-
2
u
6
3
\frac{2u^6}{3}
3
2
u
6
+
C
C
C
.Substitute back
u
=
p
+
4
u = p + 4
u
=
p
+
4
:
(
p
+
4
)
7
7
\frac{(p + 4)^7}{7}
7
(
p
+
4
)
7
-
2
(
p
+
4
)
6
3
\frac{2(p + 4)^6}{3}
3
2
(
p
+
4
)
6
+
C
C
C
.
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\newline
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(
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