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Evaluate the expression for c=3c = 3.\newlineWrite your answer in simplest form.\newlinec−5−c+2=\frac{c - 5}{-c + 2} = __

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Full solution

Q. Evaluate the expression for c=3c = 3.\newlineWrite your answer in simplest form.\newlinec−5−c+2=\frac{c - 5}{-c + 2} = __
  1. Identify Expression: Identify the expression after substituting c=3c = 3\newlineSubstitute 33 for cc in c−5−c+2\frac{c - 5}{-c + 2}.\newline3−5−3+2\frac{3 - 5}{-3 + 2}
  2. Substitute and Simplify: Evaluate 3−53 - 5\newline3−5=−23 - 5 = -2\newlineNumerator: −2-2
  3. Evaluate Numerator: Evaluate −3+2-3 + 2−3+2=−1-3 + 2 = -1Denominator: −1-1
  4. Evaluate Denominator: −2/(−1)-2/(-1)\newlineRewrite the fraction in simplest form.\newlineDivide both −2-2 and −1-1 by −1-1 to simplify.\newline−2/(−1)=2-2/(-1) = 2

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