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Evaluate -a+(-b) where a=6.05 and b=3.611.

Evaluate −a+(−b) -a+(-b) where a=6.05 a=6.05 and b=3.611 b=3.611 .

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Full solution

Q. Evaluate −a+(−b) -a+(-b) where a=6.05 a=6.05 and b=3.611 b=3.611 .
  1. Identify values for substitution: Identify the values of aa and bb that need to be substituted into the expression −a+(−b)-a+(-b).
    a=6.05a = 6.05
    b=3.611b = 3.611
  2. Substitute values into expression: Substitute the values of aa and bb into the expression.−a+(−b)-a+(-b) becomes −6.05+(−3.611)-6.05+(-3.611)
  3. Perform addition of negative numbers: Perform the addition of the two negative numbers.−6.05+(−3.611)=−6.05−3.611-6.05 + (-3.611) = -6.05 - 3.611
  4. Calculate sum of negative numbers: Calculate the sum of −6.05-6.05 and −3.611-3.611. \newline−6.05−3.611=−9.661-6.05 - 3.611 = -9.661
  5. Check for errors: Check the result for any mathematical errors. The addition of two negative numbers has been performed correctly, and the result is negative.

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