estion listQuestion 23Question 24Question 25uestion 26Solve by the method of your choice.Twenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is \$\(1000\), second prize is \$\(500\), and third prize is \$\(100\), in how many different ways can the prizes be awarded?\(\newline\)There are \(\square\) different ways in which the prizes can be awarded.\(\newline\)(Simplify your answer.)
Q. estion listQuestion 23Question 24Question 25uestion 26Solve by the method of your choice.Twenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is \$\(1000\), second prize is \$\(500\), and third prize is \$\(100\), in how many different ways can the prizes be awarded?\(\newline\)There are \(\square\) different ways in which the prizes can be awarded.\(\newline\)(Simplify your answer.)
Identify Problem Type: Identify the problem as a permutation since the order in which the prizes are awarded matters. There are 22 people and 3 prizes, so we need to calculate the number of ways to choose 3 winners out of 22 where the order is important.
Use Permutations Formula: Use the formula for permutations, which is P(n,k)=(n−k)!n!, where n is the total number of items and k is the number of items to choose. Here, n is 22 and k is 3.
Calculate Permutation: Calculate the permutation: P(22,3)=(22−3)!22!=19!22!.
Simplify Expression: Simplify the expression by canceling out the common factorial terms: 19!22!=22×21×20.
Perform Multiplication: Perform the multiplication: 22×21×20=9240.
More problems from Multiply and divide rational numbers: word problems