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estion list\newlineQuestion 2323\newlineQuestion 2424\newlineQuestion 2525\newlineuestion 2626\newlineSolve by the method of your choice.\newlineTwenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is \$\(1000\), second prize is \$\(500\), and third prize is \$\(100\), in how many different ways can the prizes be awarded?\(\newline\)There are \(\square\) different ways in which the prizes can be awarded.\(\newline\)(Simplify your answer.)

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Q. estion list\newlineQuestion 2323\newlineQuestion 2424\newlineQuestion 2525\newlineuestion 2626\newlineSolve by the method of your choice.\newlineTwenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is \$\(1000\), second prize is \$\(500\), and third prize is \$\(100\), in how many different ways can the prizes be awarded?\(\newline\)There are \(\square\) different ways in which the prizes can be awarded.\(\newline\)(Simplify your answer.)
  1. Identify Problem Type: Identify the problem as a permutation since the order in which the prizes are awarded matters. There are 2222 people and 33 prizes, so we need to calculate the number of ways to choose 33 winners out of 2222 where the order is important.
  2. Use Permutations Formula: Use the formula for permutations, which is P(n,k)=n!(nk)!P(n, k) = \frac{n!}{(n - k)!}, where nn is the total number of items and kk is the number of items to choose. Here, nn is 2222 and kk is 33.
  3. Calculate Permutation: Calculate the permutation: P(22,3)=22!(223)!=22!19!P(22, 3) = \frac{22!}{(22 - 3)!} = \frac{22!}{19!}.
  4. Simplify Expression: Simplify the expression by canceling out the common factorial terms: 22!19!=22×21×20\frac{22!}{19!} = 22 \times 21 \times 20.
  5. Perform Multiplication: Perform the multiplication: 22×21×20=924022 \times 21 \times 20 = 9240.

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