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Emma is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 
0.475%. If Emma would like to end up with 
$14,000 after 14 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Emma is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.475% 0.475 \% . If Emma would like to end up with $14,000 \$ 14,000 after 1414 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Emma is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.475% 0.475 \% . If Emma would like to end up with $14,000 \$ 14,000 after 1414 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $14,000\$14,000\newlineii (interest rate per period) = 0.475%0.475\% per month, which is 0.004750.00475 in decimal form\newlinenn (number of periods) = 1414 months\newlineWe need to find the value of dd (the amount invested at the end of each period).
  2. Convert Interest Rate: Convert the interest rate from a percentage to a decimal. i=0.475%=0.475100=0.00475i = 0.475\% = \frac{0.475}{100} = 0.00475
  3. Plug Values into Formula: Plug the values into the formula to solve for dd.A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)$14,000=d×((1+0.00475)1410.00475)\$14,000 = d \times \left(\frac{(1 + 0.00475)^{14} - 1}{0.00475}\right)
  4. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newline(1+0.00475)141(1 + 0.00475)^{14} - 1\newline= (1.00475)141(1.00475)^{14} - 1\newline= 1.06967811.069678 - 1\newline= 0.0696780.069678
  5. Divide by Interest Rate: Divide the result by the interest rate ii. \newline0.0696780.00475\frac{0.069678}{0.00475}\newline=14.664842105263158= 14.664842105263158
  6. Solve for d: Solve for d by dividing AA by the result from Step 55.\newlined=$14,00014.664842105263158d = \frac{\$14,000}{14.664842105263158}\newlined954.545d \approx 954.545
  7. Round to Nearest Dollar: Round the result to the nearest dollar. d$955d \approx \$955

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