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Emilio just returned from a spring break volunteer trip. He is shopping for a photo album that will showcase his photos from the trip. The albums range in photo capacity and orientation.\newlineThe probability that a photo album holds under 200200 photos is 0.70.7, the probability that it is oriented horizontally is 0.30.3, and the probability that it holds under 200200 photos and is oriented horizontally is 0.20.2.\newlineWhat is the probability that a randomly chosen photo album holds under 200200 photos or is oriented horizontally?\newlineWrite your answer as a whole number, decimal, or simplified fraction.

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Q. Emilio just returned from a spring break volunteer trip. He is shopping for a photo album that will showcase his photos from the trip. The albums range in photo capacity and orientation.\newlineThe probability that a photo album holds under 200200 photos is 0.70.7, the probability that it is oriented horizontally is 0.30.3, and the probability that it holds under 200200 photos and is oriented horizontally is 0.20.2.\newlineWhat is the probability that a randomly chosen photo album holds under 200200 photos or is oriented horizontally?\newlineWrite your answer as a whole number, decimal, or simplified fraction.
  1. Define Events: Let's call the event where a photo album holds under 200200 photos event AA, and the event where an album is oriented horizontally event BB. We know that: P(A)=0.7P(A) = 0.7 (probability that an album holds under 200200 photos) P(B)=0.3P(B) = 0.3 (probability that an album is oriented horizontally) P(A and B)=0.2P(A \text{ and } B) = 0.2 (probability that an album holds under 200200 photos and is oriented horizontally)
  2. Apply Addition Rule: We use the Addition Rule of Probability to find P(A or B)P(A \text{ or } B):P(A or B)=P(A)+P(B)P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)
  3. Calculate Probability: Now we plug in the values we have:\newlineP(A or B)=0.7+0.30.2P(A \text{ or } B) = 0.7 + 0.3 - 0.2
  4. Final Result: Doing the calculation gives us:\newlineP(A or B)=1.00.2P(A \text{ or } B) = 1.0 - 0.2\newlineP(A or B)=0.8P(A \text{ or } B) = 0.8

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