ehallpass $\newline$ Student and Parent... $\newline$ C $\newline$ Clever | Portal $\newline$ Track & Field PRP Pr... $\newline$ Performance Matters $\newline$ Welcor $\newline$ Question $6$ of $11$ $\newline$ Submit Test $\newline$ MCPS Geo Unit $07$ CA F $\newline$ Label the two missing side lengths of the triangle shown. $\newline$ $5(5\sqrt{2})/(2)5\sqrt{2}5\sqrt{3}10$ $\newline$ Previous

Full solution

Q. ehallpass

\newline

Student and Parent...

\newline

\newline

Clever | Portal

\newline

Track & Field PRP Pr...

\newline

Performance Matters

\newline

Welcor

\newline

Question

6

11

\newline

Submit Test

\newline

MCPS Geo Unit

07

CA F

\newline

Label the two missing side lengths of the triangle shown.

\newline

5(5\sqrt{2})/(2)5\sqrt{2}5\sqrt{3}10

\newline

Identify Triangle Type: Identify the type of triangle. It's a right triangle with one side labeled as $5$ and the hypotenuse as $5\sqrt{2}$ .
Use Pythagorean Theorem: Use the Pythagorean theorem to find the missing side. Let's call the missing side 'a'. So, $a^2 + 5^2 = (5\sqrt{2})^2$ .
Simplify Equation: Simplify the equation. $a^2 + 25 = 50$ .
Subtract $25$ : Subtract $25$ from both sides. $a^2 = 50 - 25$ .
Calculate a^ $2$ : Calculate the value of $a^2$ . $a^2 = 25$ .
Find Value of 'a': Find the value of 'a' by taking the square root of both sides. $a = \sqrt{25}$ .
Calculate Square Root: Calculate the square root of $25$ . $a = 5$ .
Correct Mistake: Now we have both missing sides. The sides are $5$ and $5\sqrt{2}$ , but wait, the hypotenuse is $5\sqrt{2}$ , so we made a mistake. The side cannot be the same length as the hypotenuse.