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Assignment 4

Find the following:
(a) 
int16x^(-3)dx quad(x!=0)
(d) 
int2e^(-2x)dx
(b) 
int9x^(8)dx
(e) 
int(4x)/(x^(2)+1)dx
(c) 
int(x^(5)-3x)dx
(f) 
int(2ax+b)(ax^(2)+bx)^(7)dx

Edit\newline33\newlineAssignment 44\newline11. Find the following:\newline(a) 16x3dx(x0) \int 16 x^{-3} d x \quad(x \neq 0) \newline(d) 2e2xdx \int 2 e^{-2 x} d x \newline(b) 9x8dx \int 9 x^{8} d x \newline(e) 4xx2+1dx \int \frac{4 x}{x^{2}+1} d x \newline(c) (x53x)dx \int\left(x^{5}-3 x\right) d x \newline(f) (2ax+b)(ax2+bx)7dx \int(2 a x+b)\left(a x^{2}+b x\right)^{7} d x

Full solution

Q. Edit\newline33\newlineAssignment 44\newline11. Find the following:\newline(a) 16x3dx(x0) \int 16 x^{-3} d x \quad(x \neq 0) \newline(d) 2e2xdx \int 2 e^{-2 x} d x \newline(b) 9x8dx \int 9 x^{8} d x \newline(e) 4xx2+1dx \int \frac{4 x}{x^{2}+1} d x \newline(c) (x53x)dx \int\left(x^{5}-3 x\right) d x \newline(f) (2ax+b)(ax2+bx)7dx \int(2 a x+b)\left(a x^{2}+b x\right)^{7} d x
  1. Problem (a): \newline**Problem (a):** \newlineReasoning: Use the power rule for integration, xndx=xn+1n+1+C\int x^n \, dx = \frac{x^{n+1}}{n+1} + C for n1n \neq -1. \newlineCalculation: 16x3dx=16x3dx=16x3+13+1+C=8x2+C\int 16x^{-3} \, dx = 16 \int x^{-3} \, dx = 16 \cdot \frac{x^{-3+1}}{-3+1} + C = -8x^{-2} + C
  2. Problem (b): \newline**Problem (b):** \newlineReasoning: Apply the power rule for integration. \newlineCalculation: 9x8dx=9x8+18+1+C=x9+C\int 9x^8 \, dx = 9 \cdot \frac{x^{8+1}}{8+1} + C = x^9 + C

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