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$E$ represents the anchor's elevation relative to the water's surface (in meters) as a function of time $t$ (in seconds). $\newline$ $E=-2.4t+75$ $\newline$ How far does the anchor drop every $5$ seconds? $\newline$ meters

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Understanding integers

Full solution

Q.

E

represents the anchor's elevation relative to the water's surface (in meters) as a function of time

t

(in seconds).

\newline

E=-2.4t+75

\newline

How far does the anchor drop every

5

seconds?

\newline

meters

Identify Function: Identify the given function and what it represents. $\newline$ The function $E=-2.4t+75$ represents the anchor's elevation relative to the water's surface in meters as a function of time in seconds.
Determine Change: Determine the change in elevation after $5$ seconds. $\newline$ To find out how far the anchor drops every $5$ seconds, we need to calculate the change in elevation from time $t$ to time $t+5$ .
Calculate Starting Elevation: Calculate the elevation at the starting time. $\newline$ Let's calculate the elevation at time $t=0$ seconds using the given function $E=-2.4t+75$ . $\newline$ $E(0) = -2.4(0) + 75 = 75$ meters.
Calculate Elevation After $5$ Seconds: Calculate the elevation after $5$ seconds. $\newline$ Now, let's calculate the elevation at time $t=5$ seconds using the same function. $\newline$ $E(5) = -2.4(5) + 75 = -12 + 75 = 63$ meters.
Find Elevation Difference: Find the difference in elevation to determine the drop. $\newline$ The drop in elevation over $5$ seconds is the difference between the elevation at time $t=0$ seconds and $t=5$ seconds. $\newline$ Drop = $E(0) - E(5) = 75$ meters - $63$ meters = $12$ meters.

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