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Let’s check out your problem:
e
2
7
2
\quad 27^{2}
2
7
2
as a power of
9
9
9
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Math Problems
Algebra 1
Evaluate integers raised to positive rational exponents
Full solution
Q.
e
2
7
2
\quad 27^{2}
2
7
2
as a power of
9
9
9
Recognize Power of
9
9
9
:
Recognize that
27
27
27
is a power of
9
9
9
.
27
=
9
×
3
27 = 9 \times 3
27
=
9
×
3
=
3
3
= 3^3
=
3
3
Rewrite Using Base:
Rewrite
27
27
27
using the base of
9
9
9
.
\newline
27
=
3
3
27 = 3^3
27
=
3
3
\newline
=
(
9
1
/
2
)
3
= (9^{1/2})^3
=
(
9
1/2
)
3
Apply Power Rule:
Apply the power of a power rule.
\newline
(
9
1
2
)
3
=
9
3
2
(9^{\frac{1}{2}})^3 = 9^{\frac{3}{2}}
(
9
2
1
)
3
=
9
2
3
Square to Find
2
7
2
27^2
2
7
2
:
Square the expression to find
2
7
2
27^2
2
7
2
as a power of
9
9
9
.
\newline
(
9
3
/
2
)
2
=
9
3
/
2
×
2
(9^{3/2})^2 = 9^{3/2 \times 2}
(
9
3/2
)
2
=
9
3/2
×
2
\newline
=
9
3
= 9^3
=
9
3
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