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During the intermission of the school play, the drama class at Danville High School is offering refreshments. The goal is to make more than $\$290$ in revenue tonight by selling beverages for $\$1$ and snacks for $\$2$ . $\newline$ Select the inequality in standard form that describes this situation. Use the given numbers and the following variables. $\newline$ $x =$ the number of beverages sold $\newline$ $y =$ the number of snacks sold $\newline$ Choices: $\newline$ (A) $x + 2y > 290$ $\newline$ (B) $1 + x + 2 + y > 290$ $\newline$ (C) $1 + x + 2 + y < 290$ $\newline$ (D) $x + 2y < 290$

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Write two-variable inequalities: word problems

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Q. During the intermission of the school play, the drama class at Danville High School is offering refreshments. The goal is to make more than

\$290

in revenue tonight by selling beverages for

\$1

and snacks for

\$2

.

\newline

Select the inequality in standard form that describes this situation. Use the given numbers and the following variables.

\newline

x =

the number of beverages sold

\newline

y =

the number of snacks sold

\newline

Choices:

\newline

(A)

x + 2y > 290

\newline

(B)

1 + x + 2 + y > 290

\newline

(C)

1 + x + 2 + y < 290

\newline

(D)

x + 2y < 290

Determine Revenue Goal Inequality: We need to determine the inequality that represents the revenue goal from selling beverages and snacks. The beverages are sold for $\$1$ each, and the snacks are sold for $\$2$ each. The variables given are $x$ for the number of beverages sold and $y$ for the number of snacks sold. The revenue from beverages is therefore $x$ dollars, and the revenue from snacks is $2y$ dollars.
Calculate Total Revenue: To find the total revenue, we add the revenue from beverages and the revenue from snacks. This gives us the expression $x + 2y$ , which represents the total revenue from selling $x$ beverages and $y$ snacks.
Set Revenue Goal Inequality: The goal is to make more than $\$290$ in revenue. Therefore, the inequality that represents this situation is that the total revenue $(x + 2y)$ must be greater than $\$290$ . The inequality in standard form that describes this situation is $x + 2y > 290$ .

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