Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Does the point (−1,−5)(-1, -5) satisfy the equation y=2x2+6x−1y = 2x^2 + 6x - 1?\newlineChoices:\newline(A)yes\newline(B)no

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 8right chevron icon
Is (x, y) a solution to the nonlinear equation?right chevron icon

Full solution

Q. Does the point (−1,−5)(-1, -5) satisfy the equation y=2x2+6x−1y = 2x^2 + 6x - 1?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute x-value: Substitute the xx-value from the point into the equation to find yy.y=2(−1)2+6(−1)−1y = 2(-1)^2 + 6(-1) - 1y=2(1)−6−1y = 2(1) - 6 - 1y=2−6−1y = 2 - 6 - 1y=−5y = -5
  2. Compare y-values: Compare the calculated yy-value with the yy-value from the point.\newlineCalculated y=−5y = -5, Point's y=−5y = -5\newlineSince both values are the same, the point satisfies the equation.

More problems from Is (x, y) a solution to the nonlinear equation?

Question
If −x2=−5y2+y3 -x^{2}=-5 y^{2}+y^{3} then find dydx \frac{d y}{d x} at the point (2,1) (2,1) .\newlineAnswer: dydx∣(2,1)= \left.\frac{d y}{d x}\right|_{(2,1)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If y2=2x2+y y^{2}=2 x^{2}+y then find dydx \frac{d y}{d x} at the point (1,2) (1,2) .\newlineAnswer: dydx∣(1,2)= \left.\frac{d y}{d x}\right|_{(1,2)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If −3−3x2−5y=−y3−y2 -3-3 x^{2}-5 y=-y^{3}-y^{2} then find dydx \frac{d y}{d x} at the point (−1,−2) (-1,-2) .\newlineAnswer: dydx∣(−1,−2)= \left.\frac{d y}{d x}\right|_{(-1,-2)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If 5x2−5−3y2=0 5 x^{2}-5-3 y^{2}=0 then find dydx \frac{d y}{d x} at the point (4,5) (4,5) .\newlineAnswer: dydx∣(4,5)= \left.\frac{d y}{d x}\right|_{(4,5)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If −2x2+y2+y3+3x=0 -2 x^{2}+y^{2}+y^{3}+3 x=0 then find dydx \frac{d y}{d x} at the point (2,1) (2,1) .\newlineAnswer: dydx∣(2,1)= \left.\frac{d y}{d x}\right|_{(2,1)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If y2+3x3=2y y^{2}+3 x^{3}=2 y then find dydx \frac{d y}{d x} at the point (−1,3) (-1,3) .\newlineAnswer: dydx∣(−1,3)= \left.\frac{d y}{d x}\right|_{(-1,3)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If 4x−4−4x2=y2−y3 4 x-4-4 x^{2}=y^{2}-y^{3} then find dydx \frac{d y}{d x} at the point (1,2) (1,2) .\newlineAnswer: dydx∣(1,2)= \left.\frac{d y}{d x}\right|_{(1,2)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If 0=4+5x3−y2 0=4+5 x^{3}-y^{2} then find dydx \frac{d y}{d x} at the point (1,−3) (1,-3) .\newlineAnswer: dydx∣(1,−3)= \left.\frac{d y}{d x}\right|_{(1,-3)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
If −y3−y+2+y2=x2 -y^{3}-y+2+y^{2}=x^{2} then find dydx \frac{d y}{d x} at the point (4,−2) (4,-2) .\newlineAnswer: dydx∣(4,−2)= \left.\frac{d y}{d x}\right|_{(4,-2)}=
Get tutor helpright-arrow

Posted 2 months ago

Question
Given y=−2sin⁡(2x) y=-2 \sin (2 x) , find dydx \frac{d y}{d x} .\newlineAnswer: dydx= \frac{d y}{d x}=
Get tutor helpright-arrow

Posted 2 months ago

View all (22)