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Does the point (1, 10)(1,\ 10) satisfy the inequality y<9x+1y < 9x + 1?\newlineChoices:\newline(A)yes\newline(B)no

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Which equation has a constant of proportionality equal to 00.2525 ?\newlineChoose 11 answer:\newline(A) y=25x y=25 x \newline(B) y=52x y=\frac{5}{2} x \newline(C) y=14x y=\frac{1}{4} x \newline(D) y=125x y=\frac{1}{25} x
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Posted 3 months ago

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Consider the following problem:\newlineThe total number of subscribers Zhang Wei has for his video page is changing at a rate of r(t)=21−2t r(t)=21-2 t subscribers per week (where t t is the time in weeks). At time t=8 t=8 weeks, Zhang Wei has 120120 subscribers. How many subscribers does Zhang Wei have by week 2020 ?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) r(20)−r(8)+120 r(20)-r(8)+120 \newline(B) ∫2020r(t)dt \int_{20}^{20} r(t) d t \newline(C) ∫820r(t)dt+120 \int_{8}^{20} r(t) d t+120 \newline(D) r(20) r(20)
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Posted 3 months ago

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Anjali was given this problem:\newlineA person stands at a distance of 1212 meters east of an intersection and watches a car driving away from the intersection to the north at 44 meters per second. At a certain instant t0 t_{0} , the car is at distance n(t0) n\left(t_{0}\right) of 99 meters from the intersection. What is the rate of change of the distance d(t) d(t) between the car and the person at that instant?\newlineWhich equation should Anjali use to solve the problem?\newlineChoose 11 answer:\newline(A) tan⁡[d(t)]=n(t)12 \tan [d(t)]=\frac{n(t)}{12} \newline(B) d(t)=12⋅n(t)2 d(t)=\frac{12 \cdot n(t)}{2} \newline(C) d(t)+12+n(t)=180 d(t)+12+n(t)=180 \newline(D) [d(t)]2=122+[n(t)]2 [d(t)]^{2}=12^{2}+[n(t)]^{2}
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Posted 3 months ago

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In one kind of chemical reaction, unconverted reactants change into converted reactants.\newlineThe fraction a a of reactants that have been converted increases at a rate proportional to the product of the fraction of converted reactants and the fraction of unconverted reactants.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) dadt=ka1−a \frac{d a}{d t}=\frac{k a}{1-a} \newline(B) dadt=ka(1−a) \frac{d a}{d t}=k a(1-a) \newline(c) dadt=ka(1−a) \frac{d a}{d t}=\frac{k}{a(1-a)} \newline(D) dadt=ka2 \frac{d a}{d t}=k a^{2}
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Posted 3 months ago

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Juan tried to perform the following addition and reduce to lowest terms: \newline(2x−1)+(3x+1)(\frac{2}{x-1})+(\frac{3}{x+1})\newlineThis is his work:\newline\begin{align*}\(\newline&=\frac{2}{x-1}+\frac{3}{x+1},(\newline\)&=\frac{2+3}{x-1+x+1},(\newline\)&=\frac{5}{2x}\newline\end{align*}\)\newlineWhat mistake did he make in combining the rational expressions?\newlineHe forgot to factor the denominator.\newlineHe failed to find a common denominator.\newlineHe incorrectly applied the distributive property.\newlineHe made a mistake in simplifying the numerators.
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Posted 2 months ago

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Select the values that make the inequality \newlinev>−1v > -1 true.\newline(Numbers written in order from least to greatest going across.)\newlineAnswer\newline\newline−9-9\newline−6-6\newline−4-4\newline\newline−2-2\newline−1.1-1.1\newline−1.01-1.01\newline\newline−1.001-1.001\newline−1-1\newline−0.999-0.999\newline\newline−9-900\newline−9-911\newline−9-922\newline\newline−9-933\newline−9-944\newline−9-955\newline\newlinecharines
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Posted 2 months ago

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Use the coordinates below to determine if △ABC \triangle ABC and △DEF \triangle DEF are congruent\newline△ABC \triangle ABC :A(2,−8) A(2,-8) ,B(−5,−2) B(-5,-2) ,C(−7,3) C(-7,3) ;△DEF \triangle DEF :D(−9,7) D(-9,7) ,E(−11,12) E(-11,12) ,F(−2,1) F(-2,1) \newlineAnswer Attempt △DEF \triangle DEF 00\newline△DEF \triangle DEF 11\newlineAre the triangles congruent (yes or no) △DEF \triangle DEF 22
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Posted 2 months ago

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Select the values that make the inequality \newliner>−4 r > -4 true.\newline(Numbers written in order from least to greatest going across.)\newlineAnswer Attempt 11 out of 22\newline\newline−12-12\newline−9-9\newline−7-7\newline\newline−5-5\newline−42-4^{2}\newline−4.01-4.01\newline\newline−4.001-4.001\newline−4-4\newline−3.999-3.999\newline\newline−12-1200\newline−12-1211\newline−12-1222\newline\newline−12-1233\newline−12-1244\newline−12-1255
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Posted 2 months ago

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Select the values that make the inequality \newliner>−4r > -4 true.\newline(Numbers written in order from least to greatest going across.)\newlineComplete 28x28x\newlineAnswer Attempt 200200 of 22\newline−12-12\newline−9-9\newline−7-7\newline−5-5\newline−4.1-4.1\newline−4.01-4.01\newline28x28x00\newline28x28x11\newline28x28x22\newline28x28x33\newline28x28x44\newline28x28x55\newline28x28x66\newline28x28x77\newline28x28x88\newlineSubmit Answer
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Posted 2 months ago

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Question 44\newline0.140.14//11 pt \newline2\sqrt{2}\newlineA scientific study was conducted to determine the hours of sleep that college students get per night. The study surveyed 3232 college students and obtained the following data:\newline\{:[7.1,\,7.4,\,7,\,8.1,\,7.6,\,6.3,\,7,\,6,\,6.8,\,6.4,\,7.5,\,7.5,\,8,\,6.1,\,8.4,\,7.3,\,8.5,\,6.6,\,7,\,7.5,\,6.6,\,7.1,\,7,\,6.2,\,6.6,\,7.5,\,],[5.9,\,7.7,\,6.7,\,6.4,\,7.7,\,6.9]:}\newlineConstruct a 95%95\% confidence interval for the average hours of sleep per night that college students get.\newline\{:[\bar{x}=\square],[\alpha=\square=\square],[t_{(9)}=\square]:}\newlineMargin of Error: \newlineE=E=\newlineWe are \newline95%95\% confident that college students get an average of between and hours of sleep per night. hours
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Posted 2 months ago

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