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Does (1,3)(1,\,3) make the inequality 2x+6y202x + 6y \geq 20 true?\newlineChoices:\newline(A)yes\newline(B)no

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Q. Does (1,3)(1,\,3) make the inequality 2x+6y202x + 6y \geq 20 true?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute values into inequality: Substitute the values (1,3)(1, 3) into the inequality 2x+6y202x + 6y \geq 20. The substituted inequality is 2(1)+6(3)202(1) + 6(3) \geq 20.
  2. Calculate left side: Calculate the left side of the inequality 2(1)+6(3)2(1) + 6(3). Simplify it to get 2+182 + 18.
  3. Find sum: Add the numbers together to find the sum. 2+182 + 18 equals 2020.
  4. Check inequality: The inequality 2(1)+6(3)202(1) + 6(3) \geq 20 becomes 202020 \geq 20. Now, determine if the point (1,3)(1, 3) makes the inequality 2x+6y202x + 6y \geq 20 true. Since 2020 is equal to 2020, the inequality holds true.

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