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Does (0,6)(0, 6) make the equation y=−2x2+−2x−−6y = -2x^2 + -2x - -6 true?\newlineChoices:\newline(A)yes\newline(B)no

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Is (x, y) a solution to the nonlinear equation?right chevron icon

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Q. Does (0,6)(0, 6) make the equation y=−2x2+−2x−−6y = -2x^2 + -2x - -6 true?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute Values: Step 11: Substitute the xx and yy values from the point (0,6)(0, 6) into the equation.\newliney=–2x2+–2x−–6y = –2x^2 + –2x − –6\newlineSubstitute x=0x = 0 and y=6y = 6:\newline6=–2(0)2+–2(0)−–66 = –2(0)^2 + –2(0) − –6
  2. Simplify Equation: Step 22: Simplify the equation to check if both sides are equal.\newline6=−2(0)+−2(0)+66 = -2(0) + -2(0) + 6\newline6=0+0+66 = 0 + 0 + 6\newline6=66 = 6

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