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Divide. If there is a remainder, include it as a simplified fraction.\newline(3c36c29c)÷(c3)(3c^3 - 6c^2 - 9c) \div (c - 3)

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Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(3c36c29c)÷(c3)(3c^3 - 6c^2 - 9c) \div (c - 3)
  1. Use polynomial long division: To divide the polynomial (3c36c29c)(3c^3 - 6c^2 - 9c) by the binomial (c3)(c - 3), we will use polynomial long division.
  2. Find first term of quotient: First, we divide the leading term of the polynomial, 3c33c^3, by the leading term of the binomial, cc, to get the first term of the quotient, which is 3c23c^2.\newlineCalculation: (3c3)÷(c)=3c2(3c^3) \div (c) = 3c^2
  3. Subtract and continue division: Next, we multiply the entire binomial (c3)(c - 3) by the term we just found, 3c23c^2, and subtract the result from the original polynomial.\newlineCalculation: (c3)×3c2=3c39c2(c - 3) \times 3c^2 = 3c^3 - 9c^2\newlineSubtraction: (3c36c29c)(3c39c2)=3c29c(3c^3 - 6c^2 - 9c) - (3c^3 - 9c^2) = 3c^2 - 9c
  4. Find next term of quotient: Now, we divide the leading term of the new polynomial, 3c23c^2, by the leading term of the binomial, cc, to get the next term of the quotient, which is 3c3c.\newlineCalculation: (3c2)÷(c)=3c(3c^2) \div (c) = 3c
  5. Subtract and continue division: We multiply the entire binomial (c3)(c - 3) by the term we just found, 3c3c, and subtract the result from the new polynomial.\newlineCalculation: (c3)×3c=3c29c(c - 3) \times 3c = 3c^2 - 9c\newlineSubtraction: (3c29c)(3c29c)=0(3c^2 - 9c) - (3c^2 - 9c) = 0
  6. Complete division and find quotient: Since we have no remainder, the division is complete. The quotient is the sum of the terms we found: 3c2+3c3c^2 + 3c.

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