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Divide. If there is a remainder, include it as a simplified fraction.\newline(4z2+9z9)÷(z+3)(4z^2 + 9z - 9) \div (z + 3)

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Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(4z2+9z9)÷(z+3)(4z^2 + 9z - 9) \div (z + 3)
  1. Divide Leading Terms: We will use polynomial long division to divide (4z2+9z9)(4z^2 + 9z - 9) by (z+3)(z + 3). First, we divide the leading term of the numerator, 4z24z^2, by the leading term of the denominator, zz, to get the first term of the quotient. 4z2÷z=4z4z^2 \div z = 4z
  2. Multiply and Subtract: Now, we multiply the entire divisor (z+3)(z + 3) by the first term of the quotient (4z)(4z) and subtract the result from the original polynomial.\newline(4z)(z+3)=4z2+12z(4z)(z + 3) = 4z^2 + 12z\newlineSubtract this from the original polynomial:\newline(4z2+9z9)(4z2+12z)=3z9(4z^2 + 9z - 9) - (4z^2 + 12z) = -3z - 9
  3. Divide New Leading Term: Next, we divide the new leading term of the remainder, 3z-3z, by the leading term of the divisor, zz. \newline3z÷z=3-3z \div z = -3
  4. Multiply and Subtract: We multiply the entire divisor (z+3)(z + 3) by the new term of the quotient (3)(-3) and subtract the result from the current remainder.(3)(z+3)=3z9(-3)(z + 3) = -3z - 9Subtract this from the current remainder:(3z9)(3z9)=0(-3z - 9) - (-3z - 9) = 0
  5. Check Remainder: Since the remainder is 00, we have finished the division process. The quotient is the sum of the terms we found: 4z34z - 3.

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