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Divide. If there is a remainder, include it as a simplified fraction.\newline(6g320g2+6g)÷(g3)(6g^3 - 20g^2 + 6g) \div (g - 3)\newline______

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Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(6g320g2+6g)÷(g3)(6g^3 - 20g^2 + 6g) \div (g - 3)\newline______
  1. Divide leading terms: We will use polynomial long division to divide (6g320g2+6g)(6g^3 - 20g^2 + 6g) by (g3)(g - 3). First, we divide the leading term of the dividend, 6g36g^3, by the leading term of the divisor, gg, to get the first term of the quotient. 6g3÷g=6g26g^3 \div g = 6g^2
  2. Multiply and subtract: We multiply the entire divisor (g3)(g - 3) by the first term of the quotient (6g2)(6g^2) and subtract the result from the dividend.\newline(6g2)(g3)=6g318g2(6g^2) \cdot (g - 3) = 6g^3 - 18g^2\newlineThen we subtract this from the dividend:\newline(6g320g2+6g)(6g318g2)=20g2+18g2+6g=2g2+6g(6g^3 - 20g^2 + 6g) - (6g^3 - 18g^2) = -20g^2 + 18g^2 + 6g = -2g^2 + 6g
  3. Divide new polynomial: Next, we divide the leading term of the new polynomial, 2g2-2g^2, by the leading term of the divisor, gg, to get the next term of the quotient.\newline2g2÷g=2g-2g^2 \div g = -2g
  4. Multiply and subtract: We multiply the entire divisor (g3)(g - 3) by the second term of the quotient (2g)(-2g) and subtract the result from the new polynomial.\newline(-2g) \cdot (g - 3) = -2g^2 + 6g\(\newlineThen we subtract this from the new polynomial:\newline\$(-2g^2 + 6g) - (-2g^2 + 6g) = 0\)
  5. Complete division process: Since we have no remainder, the division process is complete. The quotient is the sum of the terms we found: \(6g^2 - 2g\).

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