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Divide. If there is a remainder, include it as a simplified fraction.\newline(4z3+10z224z)÷(z+4)(4z^3 + 10z^2 - 24z) \div (z + 4)

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Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(4z3+10z224z)÷(z+4)(4z^3 + 10z^2 - 24z) \div (z + 4)
  1. Use Polynomial Long Division: To divide the polynomial (4z3+10z224z)(4z^3 + 10z^2 - 24z) by the binomial (z+4)(z + 4), we will use polynomial long division.
  2. Find First Quotient Term: First, we divide the leading term of the polynomial, 4z34z^3, by the leading term of the binomial, zz, to get the first term of the quotient, which is 4z24z^2.\newlineCalculation: 4z3÷z=4z24z^3 \div z = 4z^2
  3. Subtract and Multiply: Next, we multiply the entire binomial (z+4)(z + 4) by the term we just found, 4z24z^2, and subtract the result from the original polynomial.\newlineCalculation: (z+4)×4z2=4z3+16z2(z + 4) \times 4z^2 = 4z^3 + 16z^2\newlineSubtraction: (4z3+10z224z)(4z3+16z2)=6z224z(4z^3 + 10z^2 - 24z) - (4z^3 + 16z^2) = -6z^2 - 24z
  4. Find Next Quotient Term: Now, we divide the leading term of the new polynomial, 6z2-6z^2, by the leading term of the binomial, zz, to get the next term of the quotient, which is 6z-6z.\newlineCalculation: 6z2÷z=6z-6z^2 \div z = -6z
  5. Repeat Subtraction and Multiplication: We multiply the entire binomial (z+4)(z + 4) by the term we just found, 6z-6z, and subtract the result from the new polynomial.\newlineCalculation: (z+4)6z=6z224z(z + 4) \cdot -6z = -6z^2 - 24z\newlineSubtraction: (6z224z)(6z224z)=0(-6z^2 - 24z) - (-6z^2 - 24z) = 0
  6. Complete Division: Since we have no remainder, the division is complete, and the quotient is the final answer.

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